If a= root 3+1 such that angle b =30° and angle a = 105° then find b
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Answered by
3
Answer:
Step-by-step explanation:
Let A, B, & C be the 3 angles of a triangle, and a, b, and c the corresponding sides opposite these angles:
A+B+C=180°
A+30+45=180°
A=180-75=105°
Using Law of Sines
sin A/a=sin C/c
c=(sin C/sin A)*a
c=(sin 45°/sin 105°)*√3+1
c=2
Answered by
0
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let A, B, & C be the 3 angles of a triangle, and a, b, and c the corresponding sides opposite these angles:
A+B+C=180°
A+30+45=180°
A=180-75=105°
Using Law of Sines
sin A/a=sin C/c
c=(sin C/sin A)*a
c=(sin 45°/sin 105°)*√3+1
c=2
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