if a = root 3 +1 upon root 3 minus 1 and b=1 upon a find a square minus b square
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root=~
~3+1÷~3-1=a
(4-~3)÷~3
4÷~3-1=a
1÷a= ~3÷(4-~3)
~3÷4-1=b
16-8~3+3÷3
19-8~3÷3=a^2
b^2=3÷9
=19-8~3÷3-1÷3
=(57-8~3-1)÷3
=(56-8~3)÷3
~3+1÷~3-1=a
(4-~3)÷~3
4÷~3-1=a
1÷a= ~3÷(4-~3)
~3÷4-1=b
16-8~3+3÷3
19-8~3÷3=a^2
b^2=3÷9
=19-8~3÷3-1÷3
=(57-8~3-1)÷3
=(56-8~3)÷3
palak126:
I want a square minus b square to check my answer
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