Math, asked by saiganesh38, 9 months ago

if a=root3+root2/root3-root2 and b=root3-root2/root3+root2 find the value of a square + b square​

Answers

Answered by nishajomon82
24

Answer:

50

Step-by-step explanation:

a = (root 3+root 2/root 3- root 2)(root 3+root 2/root 3+root 2)

a=3+2+2(root 3)(root 2)

a=5+2root 6

b=(root 3-root 2/root 3+ root 2)(root 3- root 2)

b=5- 2root 6

a square+ b square=(5+ 2 root 6) square + (5-2 root 6)square

a square + b square=25+(4)(6)+25-(4)(6)

a square + b square=25+24+(25-24)

a square + b square=49+1

a square + b square=50

Answered by dpsmr8610
3

a = (root 3+root 2/root 3- root 2)(root 3+root 2/root 3+root 2)

a=3+2+2(root 3)(root 2)

a=5+2root 6

b=(root 3-root 2/root 3+ root 2)(root 3- root 2)

b=5- 2root 6

a square+ b square=(5+ 2 root 6) square + (5-2 root 6)square

a square + b square=25+(4)(6)+25-(4)(6)

a square + b square=25+24+(25-24)

a square + b square=49+1

a square + b square=50Answer:

Step-by-step explanation:

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