If a=root3+root2/root3-root2 and b=root3-root2/root3+root2 then find asquare+b square and (a-b)whole square
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i) (√3+√2÷√3-√2)²+(√3-√2÷√3+√2)²=(√3+√2)²×(√3-√2)²+(√3-√2)²×(√3+√2)²÷(√3+√2)²×(√3-√2)²=(√3-√2)4+(√3-√2)4÷(√3)4-(√2)4=1+1=2
ii)((√3+√2÷√3-√2)-(√3-√2÷√3+√2))²=(√3+√2)²×(√3-√2)²+(√3-√2)²×(√3+√2)²-(√3+√2÷√3-√2)×(√3-√2÷√3+√2)=1+1-1=1
ii)((√3+√2÷√3-√2)-(√3-√2÷√3+√2))²=(√3+√2)²×(√3-√2)²+(√3-√2)²×(√3+√2)²-(√3+√2÷√3-√2)×(√3-√2÷√3+√2)=1+1-1=1
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