Question

.If A's height is 20% less than that of B, then how much percent is B's height is more than that of A?

Answer 1

25
As 100-20=80
20/80*100=25%

Answer 2

25% of B's height is more than that of A.

Given:

A's height is 20% less than that of B

To find:

How much percent of B's height is more than that of A.

Solution:

Let the height of B = 100

A's height is 20% less than that of B

A's height = 100 - $[100 (\frac{20}{100}) ]$

A's height = 100 - 20

A's height = 80

Difference between the heights of B and A = 100 - 80

Difference between the heights of B and A = 20

Therefore,

The required percentage is $\frac{20}{80}$ × 100 = 25%

25% of B's height is more than that of A.