Question

If A's height is 25% less than that of B,how much percent is B's height more than that of A?

Answer 1

Let height of B is 100
Then height of A is 100-25=75
Then the percentage of B's height more than that of A is
(100-75)(100)/75=33.33%

Answer 2

Answer: The B's height is $33\frac{1}{3}\%$ more than that of A's height.

Step-by-step explanation:

Let the height of B be 100

Let the height of A is 25% less than of B i.e. 100-25=75%.

So, Height of A would be

$\dfrac{75}{100}\times 100\\\\=75$

We need to find the percentage that B's height is more than A's:

Difference between A's height and B's height is given by

$100-75=25$

so, Percentage of B's height is more than A's height by

$\dfrac{25}{75}\times 100\\\\=\dfrac{1}{3}\times 100\\\\=33\dfrac{1}{3}\%$

Hence, The B's height is $33\frac{1}{3}\%$ more than that of A's height.