Math, asked by ANMOL3236, 1 year ago

If A's income is 10% less than B's income. How much % is B's income more than A's income? (With solution) and the answer is not 10 again....

Answers

Answered by arinjayjain24
42
Let’s assume B earns Rs 100 then A earns 90.

Now percentage of difference = 10/90 * 100
= 11.11 %
Answered by wifilethbridge
52

Answer:

11.11%

Step-by-step explanation:

Let the income of B be 100

We are given that  A's income is 10% less than B's income.

So, A's income = 100-\frac{10}{100}{ \times 100 = 90

Difference in income = 100-90 = 10

Now we are supposed to find How much % is B's income more than A's income

So,percentage = \frac{10}{90} \times 100 =11.11 \%

Hence  B's income is 11.11% more than A's income

Similar questions