If a's income is 10% more than b, how much %, is b's income less than a?
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Answer:
let income of b be x
then,
a=10%b+b
=10%x+x
=11x/10
now , a-b will be the difference
=11x/10-x
=x/10
so b's income is 1/10 less than a
ON CONVERTING TO %
=1/10×100%
=10%
SO B'S INCOME IS 10% LESS THAN A.
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