If A's income is 20% less than the income of B, by how much more is B's income than that of A.
Please give complete explanation.
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Answer:
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Step-by-step explanation:
A’s income = (100-20)% of B
A’s income = (100-20)% of BA’s income = (80/100)*x
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80x
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100=0.25*100
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100=0.25*100=25
A’s income = (100-20)% of BA’s income = (80/100)*xA’s income = 0.80xPercentage increase in amount of B= (amount of B – amount of A)/amount of A * 100=(x-0.80x)/0.80x*100=0.2x/0.80x*100=0.25*100=25Therefore, B’s income is 25% more than A
Answered by
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Step-by-step explanation:
A’s income = (100-20)% of B
A’s income = (80/100)*x
A’s income = 0.80x
Percentage increase in amount of B
= (amount of B – amount of A)/amount of A * 100
=(x-0.80x)/0.80x*100
=0.2x/0.80x*100
=0.25*100
=25
Therefore, B’s income is 25% more than A.
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