Question

If A's income is 30% less than B's, then how much per cent is B's income more than A’s?​

Answer 1

a's income = 30%

b's income = 100% - 30%

= 70%

Step-by-step explanation:

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Answer 2

• Let B's income be x.

• Given that A's income is 30% less than that of B.

Gives,

$\sf{\implies A's \ income = x-\dfrac{30}{100}x}$

$\sf{\implies A's \ income = \dfrac{70}{100}x}$

So here,

$\sf{\implies Difference \ in \ income = x- \dfrac{70}{100}x}$

$\sf{\implies Difference \ in \ income = \dfrac{30}{100}x}$

Now we have to calculate B's income more than that of A,

$\sf{\implies \%=\dfrac{\dfrac{30}{100}x}{\dfrac{70}{100}x}\times 100}$

$\sf{\implies \%=\dfrac{30}{70} \times 100}$

$\sf{\implies \%=\dfrac{3000}{70}}$

$\sf{\implies \%= 42.85}$

Therefore,

$\boxed{\sf{Hence \ B's \ income \ is \ 42.85\% \ more \ than \ that \ of \ A}}$