Math, asked by harshkataria4640, 10 months ago

If A’s income is 72% more than B’s, then how much % is B’s income less than A’s?

Answers

Answered by dozendreams
0

Let's assume B's income is 100.

Therefore A's income is 172 which 72 percent more than B's income.

Hence the percentage of B's income less than A's income is (A-B/A)×100=(172-100/172)×100=7200/172=41.86

So the answer is, B's income is 41.86% less than A's income.

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