If A's weight is 2/3 as that of B’s weight, what is the ratio of the weights of A &
B.
Answers
Step-by-step explanation:
Let the initial weight of A and B be ‘7x’ and ‘8x’ units respectively
Total weight of A & B = 7x + 8x = 15x
When A’s weight increases by 10% & total weight increases by 20%,
⇒ A’s increased weight = 110% of 7x = 1.1 × 7x = 7.7x
⇒ Total increased weight = 120% of 15x = 1.2 × 15x = 18x
Hence,
B’s increased weight = 18x - 7.7x = 10.3x
⇒ Increase in B’s weight = 10.3x - 8x = 2.3x
∴ Percentage increase in B’s weight = 2.3x/8x × 100=28. 75℅
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Answer:
Step-by-step explanation:
Step-by-step explanation:
Let the initial weight of A and B be ‘7x’ and ‘8x’ units respectively
Total weight of A & B = 7x + 8x = 15x
When A’s weight increases by 10% & total weight increases by 20%,
⇒ A’s increased weight = 110% of 7x = 1.1 × 7x = 7.7x
⇒ Total increased weight = 120% of 15x = 1.2 × 15x = 18x
Hence,
B’s increased weight = 18x - 7.7x = 10.3x
⇒ Increase in B’s weight = 10.3x - 8x = 2.3x
∴ Percentage increase in B’s weight = 2.3x/8x × 100=28. 75℅
hope it helps pls mark me as brainliest