Math, asked by umeshkrishnaa3865, 1 year ago

If a salary is 25% more than b's salary. By how much percentage b's salary less than a

Answers

Answered by smahiv
6

Answer:

20%

Step-by-step explanation:

B SALARY- x

A salary - x+{25/100(x)}

A salary = 125x/100

B salary = 100x/100

Difference percentage we have to take

= (125-100x) DIFFERENCE

-----------------

 125x                         *100 = 25x/125x*100

                                     1/5*100= 20%

hence, verified

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Answered by Agastya0606
1

Given:

The a's salary is 25% more than b's salary.

To find:

The percentage by which b's salary is less than a.

Solution:

Let the salary of b be x units.

So,

the salary of a is

 = x +  \frac{25}{100} x

 = x +  \frac{1}{4} x

 =  \frac{5x}{4}  \: units

Now,

the percentage by which b's salary is less than a is

 =   \frac{decrease \: in \: salary}{salary \: of \: a}  \times 100

 =  \frac{ \frac{5x}{4} - x }{ \frac{5x}{4} }  \times 100

 =   \frac{ \frac{x}{4} }{ \frac{5x}{4} }  \times 100

 =  \frac{x}{5x}  \times 100

 =  \frac{1}{5}  \times 100

 = 20\%

Hence, b's salary is less than a's salary by 20℅.

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