Question

if a sample of cuso4.5h2o contains 96g of oxygen then moles of h atoms present in the sample is

Answer 1

Answer:

Explanation:

i will say a simple trick

average of some element / no. of elements such in that compound are constant

if you see oxygen

o/9=h/10

moles of o / 9 = moles of h / 10

moles of oxygen = 6

6/9=moles of h / 10

moles of h = 60/9

no. of atoms = moles*index*Na

=60/9*10*Na

=66.67*Na atoms