If a satellite of mass 400 kg revolves around the
earth in an orbit with speed 200 m/s then its
potential energy is
(1) -1.2 MJ
(2) -8.0 MJ
(3) -16 MJ
(4) -24 MJ
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hear is answer.....
PE= -2KE
PE= -2KE = -2x1/2xm*v^2
PE= -2KE = -2x1/2xm*v^2given ,
PE= -2KE = -2x1/2xm*v^2given ,mass is 400kg, v=200m/s
PE= -2KE = -2x1/2xm*v^2given ,mass is 400kg, v=200m/son substituting we get PE=-400x200x200
PE= -2KE = -2x1/2xm*v^2given ,mass is 400kg, v=200m/son substituting we get PE=-400x200x200 =-16x10^6 J=-16 megajoules=-16MJ
PE= -2KE = -2x1/2xm*v^2given ,mass is 400kg, v=200m/son substituting we get PE=-400x200x200 =-16x10^6 J=-16 megajoules=-16MJ
HOPE , IT HELPS ...
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