if a scooterist drives at the rate of 24km/hr from his home, he reaches his work place 5 minutes late.But if he drives at the rate of 30 km/hr,he reaches his work place 4 minutes early.Find the distance between of his work place from his home . give answer with step by step.
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Answered by
424
Assume that he starts travelling to his workplace at the same time every day
Let the distance between his work place and home be 'd'
Let the actual time be 'x'
Distance = Speed * Time
Convert minutes into seconds as the units should be in kmph
As 24 kmph speed resulted in 5 minutes late, it is taken as increment
d = 24(x + 5/60) ---------------(1)
As 30 kmph speed resulted in 4 minutes early, it is taken as decrement
d = 30(x - 4/60) ----------------(2)
(1) and (2) are equal
=> 24(x + 5/60) = 30(x - 4/60)
=> 24x+2 = 30x-2
=> 30x - 24x = 2+2
=> 6x = 4
=> x = 2/3
Substitute the value of x in (1)
=> d = 24(2/3 + 5/60)
=> d = 24(9/12)
=> d = 18 km
The required answer is 18 km
Hope it helps
Let the distance between his work place and home be 'd'
Let the actual time be 'x'
Distance = Speed * Time
Convert minutes into seconds as the units should be in kmph
As 24 kmph speed resulted in 5 minutes late, it is taken as increment
d = 24(x + 5/60) ---------------(1)
As 30 kmph speed resulted in 4 minutes early, it is taken as decrement
d = 30(x - 4/60) ----------------(2)
(1) and (2) are equal
=> 24(x + 5/60) = 30(x - 4/60)
=> 24x+2 = 30x-2
=> 30x - 24x = 2+2
=> 6x = 4
=> x = 2/3
Substitute the value of x in (1)
=> d = 24(2/3 + 5/60)
=> d = 24(9/12)
=> d = 18 km
The required answer is 18 km
Hope it helps
fahadahmed1:
bhai thanks
Answered by
108
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