If a semiconductor has an intrinsic carrier concentration of 1.41 × 1016/m3, when doped with 1021/m3 phosphorous atoms, then the concentration of holes/m3 at room temperature will be
(a) 2 × 1021
(b) 2 × 1011
(c) 1.41 × 1010
(d) 1.41 × 1016
Answers
Answered by
3
Answer:
your answer is here !
Explanation:
Doping will increase the number of electrons only and not the holes. So, number of holes will be equal to number of intrinsic carrier concentration i.e., 1.41 × 1016/m3.
option D is right answer !
follow me!
Answered by
0
Answer:
(d)1.41 × 1016
Explanation:
Hope the above answer helps you. The above answer contains the correct information about your question. Please mark my answer as the brainliest and say thanks for the answer. Follow me
Similar questions