Question

if a servant lifts 10m*3 of liquid from tank which is at a depth of 40m The work done by him is 1600J then find the density of the liquid take g=10m/s2​

Answer 1

Answer:

Answer:

0.004 kg/m³

Explanation:

W = F*s => F*s*cosθ

Here θ is angle between F and s, which, in this case, is 0.

F = mg (as work is being done against gravity)

Now, m here is liquid's mass. So, m = ρV (V = volume of liquid and ρ = liquid's density)

Thus, equation becomes W = ρVg*s

Putting all of this in the equation,

1600 = ρ*10³*10*40

=> 16/4 = 1000ρ

=> 4/1000 = ρ

∴ ρ = 0.004 kg/m³

Answer 2

Explanation:

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