Question

If A
Set is a
solution of x2-7X+12
and
B is the solution set
rootx+5
5
then
AnB
per
1-26
-
016)​

Answer 1

Answer:

Given x2−7x+12=0

This is in the form ax2+bx+c=0 where, a = 1, b = -7 and c = 12

Quadratic formula is, x=2a−b±b2−4ac

By substituting the values, we get

x=2×1−(−7)±(−7)2−4×1×12=27±49−48=27±1=27±1

If x=27+1=28=4         x=27−1=26=3

∴ 4 and 3 are the roots of x2−7x+12=0