Question

If a ship sails 90km due north and then 20km due West. Find how far is it from it's starting point

Answer 1

And =92.2 km [approximate]

By Pythagoras theorem

${x}^{2} = {90}^{2} + {20}^{2}$

${x }^{2} = 8100 + 400$

$x = \sqrt{8500}$

$x = 92.19 \: km$

Hence the distance of ship from the starting point is 92.2 km [approx]

Answer 2

Answer:

92.2 km

Step-by-step explanation:

ACCORDING TO PYTHAGORAS THEORAM, ROUTE UNDER 90 SQ+20SQUARE =X

SO,X=ROUTE UNDER 8100+400=ROUTE UNDER 8500=92.19=92.2KM

THUS,SHE IS 92.2 KM FAR FROM THE STARTING POINT