Question

if a shopkeeper buy 8 mangoes at 5 dollars total and sell 6 mangoes at 5 dollar total
then. what is the percentage of PROFIT or loss?
​

Answer 1

$\sf\large{Given:}$

• The cost price of 8 mangoes=5dollars
• The selling price of 6 mangoes=5dollars

$\sf\large{To\: Find:}$

• The profit or loss percentage

$\sf\large{Solution:}$

$\sf{\implies CP\:of\:8\: mangoes=5}$

$\sf{\implies CP\:of\:1\: mangoes=\dfrac{5}{8}}$

$\sf{\implies SP\:of\:6\: mangoes=5}$

$\sf{\implies SP\:of\:1\: mangoes=\dfrac{5}{6}}$

• Find the equavilent fraction of cp and sp
• To make denominator same of the fraction
• At first we take Lcm of both fraction

$\sf{\implies lcm\:of\:8\:and\:6=24}$

• [Dividing here(24÷8=3) than multiple]

$\sf{\implies CP=\dfrac{5}{8}=\dfrac{5*3}{8*3}=\dfrac{15}{24}}$

• [Dividing again(24÷6=4) than multiple]

$\sf{\implies SP=\dfrac{5}{6}=\dfrac{5*4}{6*4}=\dfrac{20}{24}}$

• by comparing above the fraction
• we get sp>cp ,so we get profit,here

$\sf\purple{\implies P=SP-CP}$

$\sf{\implies P=\dfrac{5}{6}-\dfrac{5}{8}}$

$\sf{\implies p=\dfrac{20-15}{24}}$

$\sf\red{\implies p=\dfrac{5}{24}}$

• Now, calculating p% here

$\sf\green{\implies P\%=\dfrac{P*100}{CP}}$

$\sf{\implies P\%=\dfrac{5}{24}\div \dfrac{5}{8}*100}$

$\sf{\implies P\%=\dfrac{5}{24}*\dfrac{8}{5}*100}$

$\sf{\implies P\%=\dfrac{5*8*100}{24*5}}$

$\sf{\implies P\%=\dfrac{4000}{120}}$

$\sf\purple{\implies P\%=33.33}$

Hence,

• The shopkeeper gain of 33.33% overall

Answer 2

Well we have 2 methods to solve it.

First, basic method

Second, advance method

First

Cost price = ₹12

Selling price = ₹8

As we can see, CP > SP, that means there is loss in the whole transaction.

Loss%= (CP - SP)/CP ×100

= (12 - 8)/12 ×100

= 4/12 ×100

= 1/3 × 100

= 33.33% Ans.

SECOND

CP > SP

12–8 = 4 and

4 is 1/3rd of 12 and

1/3 is 33.33%.Ans.

Thank you