Question

if a shopkeeper buys a ball of 900 and sells it on 1000 then find the percentage of profit​

Answer 1

As per the data given in the question,

We have to find the percentage profit in the above given case.

From the data,

It is given that,

CP = Rs. 900

SP = Rs. 1000

As here, we can see that SP of the article is greater than the CP.

So, here there will be profit in this case.

So, profit will be $SP - CP$

So, profit will be $= Rs.\:1000-Rs.\:900 = Rs.\:100$

So, profit percentage will be $=\frac{Profit}{CP} \times 100\%$

So, putting the value given in the question,

We will get,

$\%Profit = \frac{100}{900} \times 100\%\\=>\%Profit = \frac{1}{9}\times 100\%\\=>\%Profit =\frac{100}{9}\%\\=>\%Profit = 11\frac{1}{9}\%$

Hence, there will be profit of $11\frac{1}{9}\%$ in this case.

Answer 2

As per the data given in the question,

In the above question, it is given that,

The selling price is 1000  

The cost price is 900

Here we have to find the profit percent.

We have to use the formula of profit,

Profit =S.P - C.P

Substituting the value in the above formula we get,

$P=1000-900\\P=100$

Therefore the profit of 100.

Percentage of profit =

Profit %

$=\frac{100\times 100}{900} \\=11.11\%$

Hence the profit is 11.11%.