Question

If a side of a squre is 6cm. Find the length of its diagonal correct to three decimal places
$\sqrt{2 = 1.414}$
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Answer 1

Answer:

8.484 cm

Step-by-step explanation:

Let the name of the square be ABCD

Take triangle ABC

AC is the diagonal

AB²+BC² = AC² (Pythagoras theorem)

6²+6²=AC²

36+36=AC²

AC²=72

AC=√72

AC=6√2

AC=6×1.414=8.484

Therefore diagonal of the sqaure = 8.484 cm.

Answer 2

Answer:

8.484

Step-by-step explanation:

we know that

each angle of a square is 90°

so, In right triangle form

By pythagorus theorm

(hypotenuse)^2=(perpendicular)^2+(base)^2

(H)^2=(6)^2+(6)^2

(H)^2=36+36

(H)^2=72

H=√72

H=6√2

H=6X1.414

H=8.484 cm^2