Question

if a side of triangle produces on both sides then show that the sum of two exterior angle at different vertices is greater then two right angle​

Answer 1

Step-by-step explanation:

A,B,C - Vertices

a,b,c - Internal Angles at vertices A,B,C respectively

b’,c’ - External Angles at vertices B,C respectively

From the figure we can say that

b’ = 180 - b = a + c ….. (1)

c’ = 180 - c = a + b ….. (2)

Adding 1 & 2

b’ + c’ = a + c + a + b

b’ + c’ = a + (a + b + c)

b’ + c’ = a + (180) … (a + b + c) = 180

Since a is an internal angle of a triangle, it has to be a positive value.

Thus proved - the sum of the external angles is more than two right angles

P. S. - I assumed that by ‘two right angles’ you mean 180 degrees.

Hope this helps.

MARK AS BRAINLIEST.