Physics, asked by anushreealevoor3718, 10 months ago

If a simple harmonic oscillator has got a displacement of 0.02m and acceleration equal to 2m/s2 at any time, the angular frequency of the oscillator is equal to ___________
a.10 rad/s
b.0.1 rad/s
c.100 rad/s
d.1 rad/s

Answers

Answered by Anonymous
4

for simple harmonic motion

acceleration a = -w^2 x

w = angular frequency

x = displacement

2 = w^2 * 0.02

w^2 = 100

w = 10 rad/s

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