Question

if a simple interest on rs. 2000 increases by rs. 40 .when the rate % increases by 2 % per annum find the time?

Answer 1

Hope this helps you out!!

Answer 2

Answer:

Required time (T) = 1 year

Step-by-step explanation:

Case 1:

Principal (P)= Rs2000

Let rate of interest = R%

Time = T years

Simple Interest(l) =Rs x

We know that,

$\boxed {I = \frac{PTR}{100}}$

$x = \frac{2000\times T\times R}{100}$

$100x = 2000\times T\times R---(1)$

According to the problem given,

Case 2:

Principal (P)=Rs 2000

Rate of interest = (R+2)%

Time = T years

Simple Interest = Rs (x+40)

$x+40=\frac{2000\times T \times (R+2)}{100}$

$\implies 100(x+40)=2000RT+4000T$

$\implies 100x+4000=2000RT+4000T$

$100x=2000RT+4000T-4000--(2)$

$Now, \\From\: (1)\: and\: (2), \:we \:get$

$2000RT+4000T-4000=2000RT$

$\implies 4000T=2000RT-2000RT+4000$

$\implies 4000T=4000$

$\implies T = \frac{4000}{4000}$

$\implies T = 1$

Therefore,

Required time (T) = 1 year

•••♪