Question

If a simple pendulum completed 30 oscillations in 60 seconds, what

is the time period of the simple pendulum?
​

Answer 1

Time period = 30/60 = 0.5 oscillations/seconds

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$\begin{gathered}\begin{gathered}\sf \large \red{\underline{ Question:-}}\\\\\end{gathered}\end{gathered}Question:−$

The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.

$\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Given:-}}\\\\\end{gathered}\end{gathered}Given:−$

The measures of two adjacent angles of a parallelogram are in the ratio 3:2.

$\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{To \: Find:-}}\\\\\end{gathered}\end{gathered}ToFind:−$

Find the measure of each of the angles of the parallelogram.

$\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Solution :- }}\\\\\end{gathered}\end{gathered}Solution:−$

$\text{ \sf suppose the angles be equal to 3x and 2x} suppose the angles be equal to 3x and 2x$

$\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}}wehaveardjacentanglesofaparallelogram=180$

$\begin{gathered}\begin{gathered}\\ \sf \underline{ \green{putting \: all \: values : }}\end{gathered}\end{gathered}puttingallvalues:$

$\begin{gathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180}{5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end{gathered}→3x+2x=180→5x=180→x=5180→x=5180→x=36$

$\begin{gathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{gathered}→3x→3×36→108→2x→2×36→72$

$\sf \large\underline{ \blue{verification }} \huge \dagverification†$

$\begin{gathered}\begin{gathered}\\ \\ \sf \to 3x + 2x = 180 \\ \\ \sf \to \: 3 \times 36 +2 \times 36 = 180 \\ \\ \sf \to \: 108 + 72 = 180 \\ \\ \sf \to \:180 = 180 \\ \\ \large \underline{ \pink{ \sf \: hence \: verified}} \huge \dag\end{gathered}\end{gathered}→3x+2x=180→3×36+2×36=180→108+72=180→180=180henceverified†$

Answer 2

Answer:

$\huge{\bf{\blue{\fbox{\underline{\color{red}{Answer}}}}}}$

Explanation:

For 30 oscillation it takes 60 sec

For one oscillation Tme period = 30/60 = 0.5 sec

Frequency = 1/ Time period

=1/2=0.5 Hz