if a simple pendulum is situated on moon identically as on Earth then what will be the ratio of the time period of the pendulum on Moon to Earth given g on earth is equal to 10 and G on moon is equal to
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Explanation:
When simple pendulum will placed on the surface of moon then its time period increases hence simple pendulum oscillates slowly. T=2π√l/g, put the value of g=1/6 because gravity on moon is one sixth as compare to the Earth.
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