Question

If a simple pendulum oscillates with an amplitude 50mm and time period of 2 sec, then its
maximum velocity is:
a) 0.10m/s
b) 0.15m/s
c) 0.8m/s
d) 0.16m/s​

Answer 1

Answer:

Explanation:

Answer

v=ω  

a  

2

−u  

2

 

​  

; when u=0,v=v  

max

​  

 

So, v  

max

​  

=ωa

[Where ω is angular velocity and a is amplitude]

v  

max

​  

=  

T

2π

​  

×a=  

2

2π

​  

×  

1000

50

​  

=0.16m/sec

Answer 2

Explanation:

v=ω

a

2

−u

2

; when u=0,v=v

max

So, v

max

=ωa

[Where ω is angular velocity and a is amplitude]

v

max

=

T

2π

×a=

2

2π

×

1000

50

=0.16m/sec