Question

if a sin theta = 1 and b tan theta = 1 find the relation between a and b​

Answer 1

Answer:

Solution:-

x = a sin theta : y = b tan theta  ....(Given)

L.H.S. = a²/x² - b²/y² = a²/(a sin theta)² - b²/(b tan theta)²

a² and b² are cancelled and then we get 

1/sin² theta - 1/sin² theta/cos² theta ...[∴ tan theta = sin theta/cos theta]

1/sin² theta - cos² theta/sin² theta

= (1-cos² theta)/sin² theta  ....[∴ sin² theta + cos² theta = 1]

sin² theta/sin² theta = 1

= R.H.S

⇒ a²/x² - b²/y²

Hence proved.

HOPE IT HELPED!!!

Answer 2

Step-by-step explanation:

we have a sinΦ=1

so. a=1/sinΦ

a=cosecΦ

also b. tanΦ=1

so. b=1/tanΦ

b=cotΦ

we have

1+cot^2Φ=cosec^2Φ

1+b^2=a^2

so i solve in simple words

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