If A=(sin x,0);B=(0,cos x),then find the length of AB
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Step-by-step explanation:
Let A(sinx,0) be (x1,y1)
B(0,cosx) be (x2,y2)
Using distance formula,
AB = √((x1-x2)^2 + (y1-y2)^2)
=√((sinx-0)^2 + (0-cosx)^2)
=√(sin square x + cos square x)
= √(1)
AB = 1 unit
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