Question

If A=(sin x,0),B=(0,cosx),then find the length of AB

Answer 1

Answer:1

Step-by-step explanation:

AB=√(0-sin^2x)^2 +( cos^2x- 0)^2

=√ sin^2x +cos^2x (Identity)

=√1

=1.

Answer 2

given,A=(sin x,0),B=(0,cosx)

AB

$= \sqrt{ {sin}^{2} + {cos}^{2} }$

= √ 1

= 1