If a small zinc rod is put into a solution of tin(II) chloride, SnCl2, tin will precipitate on the zinc rod and zinc will go into solution as Zn2+ ions. (There's more) What is your conclusion?
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Heyaa☺
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If a small zinc rod is put into a solution of tin(ll) chloride SnCl2 and tin will precipitate on the zinc rod and zinc will go into solution as Zn2 + .
Here,
The conclusion is.
2Zn + SnCl2 =》 2ZnCl + Sn.
This is a displacement reaction.
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Hope you understand..✌
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