Question

If a soil sample of weight 0.18 kg having a volume of
104 mº and dry unit weight of 1600 kg/mºis mixed
with 0.02 kg of water then the water content in the sam-
ple will be​

Answer 1

Answer:

The mass of soil solid =1600*10^-4= 0.16 then water content =0.18/0.16 -1=0.125 then mass of water in the sample =0.125*0.16=0.02 kg when again 0.02 kg water is mixed then total wt of water in the sample become =0.02 + 0.02 = 0.04.

w.c = 0.04 * 100/0.16 = 25%