Math, asked by shagunchauhan0304, 3 months ago

if a solid metallic sphere of radius 8cm is melted and recasted into spherical solid balls of radius 1cm, the n​

Answers

Answered by Jiya6282
6

\underline\red{\bold{Answer :- }}

Step-by-step explanation:

volume \: of \: sphere =  \frac{4}{3} \pi {r}^{3}

for \: solid \: metallic \: sphere \: radius =

r = 8cm

volume \:  = \LARGE \frac{4}{3}  \small\times 3.14 \times  {8}^{3}

 =  \LARGE\frac{6430.72}{3}

 = 2143.57 {cm}^{3}

for \: spherical \: solid \: balls \: radius \:  =

(R)=1 cm

volume \:  = \LARGE \frac{4}{3}   \small\times 3.14 \times  {1}^{3}

 =  \LARGE\frac{12.56}{3}

 = 4.186 {cm}^{3}

In order to find the number of balls carved from larger sphere we need to divide the larger ball to small ball,

 \LARGE\frac{2143.57}{4.186}

 = 512.08 ≈ 512 \: balls

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