Question

if a solid sphere is placed within a cube of edge 6cm,such that it touches all its six faces,find the volume of air flowing between sphere and closed cube.

Answer 1

v of cube-v of cylinder
cube
s=6cm
v=scube = 6cube =216cubic cm
sphere
r=6/2=3
v=4/3*22/7*3*3*3
113.142cubic cm
216-113.142 =101.858cubic cm

Answer 2

Answer:

The volume of air flowing between sphere and closed cube is $102.96 cm^3$

Step-by-step explanation:

Side of cube = 6 cm

Volume of cube = $Side^3 = 6^3 = 216$

We are given that a solid sphere is placed within a cube of edge 6cm,such that it touches all its six faces

So, diameter of sphere is 6 cm

Radius of sphere = $\frac{6}{2}=3 cm$

Volume of sphere =$\frac{4}{3} \pi r^3$

                              =$\frac{4}{3} \times 3.14 \times 3^3$  

                              =$113.04 cm^3$  

Volume of air flowing between sphere and closed cube :

= Volume of cube - volume of sphere

=$216 cm^3-113.04 cm^3$  

= $102.96 cm^3$

Hence  the volume of air flowing between sphere and closed cube is $102.96 cm^3$