If a solution containing 10g of NaCl and a solution containing 17g of silver nitrate are mixed, calculate the mass of silver chloride precipitated out and also calculate the mass of NaCl consumed in this reaction
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The first thing to do is to write down the reaction that is described in the question. Since the reactant and one of the product are given, we can write the balanced reaction:
NaCl + AgNO₃ → AgCl + NaNO₃
mass of NaCl = 23 + 35.5 = 58.5 g
mass of AgCl = 108 + 35.5 = 143.5 g
58.5 g of NaCl produces 143.5 g of AgCl
10 g of NaCl produces 143.5/58.5 x 10 = 24.53 g of AgCl
10g of NaCl is consumed out of 58.5 g in this reaction.
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