Question

if a solution of h2so4 contains 3.0115×10 to the power of 23 atoms of sulphur in 500ml of solution,find its normality​

Answer 1

Atoms of S in H2SO4 = 3.0115 X 10^23

1 mol H2SO4 has 1 mol S atoms

0.5 mol S atoms are present in 0.5 mol of H2SO4

moles of S = 3.0115 X 10^23 / 6.023 x 10^23 = 0.5 mol

Volume of solution = 500ml = 0.5L

Molarity = no. of moles of H2SO4/Volume of solution in L = 0.5/0.5 = 1 mol/L

n factor = 2

Normality = M x n factor = 1 x 2 = 2

Answer 2

Answer:

2N.

Explanation: