Question

If a sports car at rest accelerates uniformly to a speed of 144 km/hr in 5 s, it covers a distance of _ m.

Answer 1

Answer:

distance travelled by the car = 100 m

Step by step explanations :

given that,

a sports car at rest accelerates uniformly to a speed of 144 km/hr in 5 s

here,

initial velocity of the car = 0 m/s

[car was at rest]

final velocity of the car = 144 km/h

= 144 × 1000 m/3600 s

45 m/s

time taken to accelerates = 5 seconds

now,

we have,

initial velocity(u) = 0 m/s

final velocity(v) = 45 m/s

time taken(t) = 5 seconds

let the distance travelled by the car during acceleration be s

by the equation of motion,

v = u + at

where,

a is the acceleration

putting the values,

40 = 0 + a(5)

5a = 40

a = 40/5

a = 8 m/s²

also,

v² = u² + 2as

40² = (0)² + 2(8)s

16s = 1600

S = 1600/16

S = 100 m

so,

distance travelled by the car

= 100 meter

Answer 2

Answer:

distance travelled by car = 100 m

Step by step explanations :

initial velocity of the car(u) = 0 m/s

final velocity(v) = 144 km/h

= 144 × 5/18 = 45 m/s

time taken(t) = 5 seconds

v = u + at

40 = 0 + a(5)

5a = 40

a = 40/5

a = 8 m/s²

now,

S = ut + 1/2 at²

S = 1/2 × 8 × 5 × 5

S = 100 m

so,

distance travelled by car = 100 m