if a sports car can go from 27 m s-1 in 9.0 second what is the magnitude of its average accleration
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a=v-u/t
Where a is acceleration, v is final velocity, u is initial velocity and t is time.
So your answer is,
a=27-0/9
a=27/9
a=3
Average acceleration is 3m/s^2
Where a is acceleration, v is final velocity, u is initial velocity and t is time.
So your answer is,
a=27-0/9
a=27/9
a=3
Average acceleration is 3m/s^2
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