Question

If a sports car can go from a rest to 27m/s in 9.0 second, what is the magnitude of its average acceleration?

Answer 1

Answer:

3 m/s^2 is the answer

Explanation:

Given,

initial velocity,u=0

final velocity, v =27 m/s

time taken,t=9 sec

We know Newton's first law

v=u+at

so, putting values

27=0+a*9

27=a*9

acceleration,a=27/9

a=3m/s^2.