Physics, asked by yuri53, 1 year ago

if a sports car can go from rest to 27 m s-1 in 9.0 second, what is the magnitude of its average acceleration?

Answers

Answered by jordanpiper6p6ctym

A=vf-vi/t

vf=27m s-1
vi=0 m s-1
t= 9.0s

A=27-0/9 = 3

Acceleration is just the rate of change of velocity.
Because velocity is a vector, magnitude tells us how quickly this change occurs.

Therefore the magnitude of acceleration would be 3 m/s^2 (3 meters per second squared).

Answered by krishna210398

Answer:

A=vf-vi/t

vf=27m s-1

vi=0 m s-1

t= 9.0s

A=27-0/9 = 3 the correct answer

Explanation:

In mechanics, acceleration is the charge of change of the velocity of an item with admire to time. Accelerations are vector portions (in that they have importance and route).The orientation of an object's acceleration is given by means of the orientation of the net force performing on that object. The significance of an object's acceleration, as described by Newton's second law, is the mixed impact of two causes:

the net balance of all external forces appearing onto that item — value is immediately proportional to this net ensuing force;

that object's mass, relying at the materials out of which it is made — magnitude is inversely proportional to the item's mass.

The SI unit for acceleration is metre in line with 2nd squared (m⋅s−2,

as an example, while a car starts offevolved from a standstill (0 speed, in an inertial frame of reference) and travels in a instantly line at increasing speeds, it is accelerating inside the course of tour. If the car turns, an acceleration takes place towards the new route and modifications its movement vector.

The acceleration of the automobile in its contemporary path of motion is called a linear (or tangential all through round motions) acceleration, the reaction to which the passengers on board enjoy as a pressure pushing them lower back into their seats. whilst changing route, the effecting acceleration is known as radial (or centripetal at some point of circular motions) acceleration, the reaction to which the passengers enjoy as a centrifugal pressure. If the rate of the car decreases, this is an acceleration inside the opposite path and mathematically a poor, occasionally known as deceleration or retardation.