Question

If a spring has a stiffness of 950nm-1 what work will be done in extending the spring by 60mm?

Answer 1

Answer:

1.75 J

Explanation:

Here is your answer hope u get it...

Answer 2

Answer:

The answer is

W = 1.75 J

Explanation:

When an object moves over a distance by an externally applied, at least a portion of that force must be applied in the directions of the movement. This is known as work in mechanics. The combination of an organism's movement and the element of the applied pressure that is directed in the directions of the object's displacement is known as the work performed by a force.

By calculating the path length by the element of the pressure applied along the path, work can be calculated if the pressure is constant. The work W is directly proportional to the force f times the wavelength d, or W = fd, to algebraic describe this idea. The work is W = fd cos if the force is applied at an angle of to the movement.

$K=950Nm^{-1}$

$w=?$

$n=60mm$

   $=\frac{60}{1000} m$

 = 0.06 m

Therefore work done by spring

$Ws=\frac{1}{2} Kx^{2}$

     $=\frac{1}{2} *950*(0.06)^{2}$

     $=475*0.0036$

     $= 1.75J$

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