if a sq +9 /a sq =31, what is the value of a-3/a
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Answer:
a²+9/a=31
a²+9=31a
a=a²+9/31
So a-3/a
= a²+9/31 +3 ÷a²+9/31
=31a²+9+93/31×31/a²+9
=31a²+102/a²+9
The value of the equation is 3a²+102/a+9
Hope this helps you friend
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