Question

if a square + 1 upon a square is equal to 47 find a cube + 1 upon a cube​

Answer 1

AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• a² + 1/a² =47

${\sf{\green{\underline{\large{To\:find}}}}}$

• a³ + 1/a³

${\sf{\pink{\underline{\Large{Explanation}}}}}$

• We know that (X+y)² = x²+y²+2xy

Now

______________________________

(a + 1/a )² = a² + 1/a² +2

=>(a + 1/a )² = 47 +2

=>(a + 1/a )² = 49

=>a+ 1/a = 7

______________________________

we know the formula of a³+b³

• a³+b³= (a² + 1/a² + a × 1/a ) (a + 1/a)

¶utting values

______________________________

a³+b³= (47 +1) (7)

=>a³+b³= (48) (7)

=>a³+b³= (336)

______________________________

Hence value of a³+b³ is (336)

Answer 2

Answer:

anwer is 7 and 332

are u in class 9th

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