if a square ABCD AD=(3x-7) CM and BC = (X + 3) cm .find the length of AD
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all the sides of square is equal
then,
3x-7=x+3
3x-x=3+7
2x=10
x=10/2
x=5
the length of AD is (3x-7)
x=5
3×5-7
15-7
8
then the length of AD is 8
then,
3x-7=x+3
3x-x=3+7
2x=10
x=10/2
x=5
the length of AD is (3x-7)
x=5
3×5-7
15-7
8
then the length of AD is 8
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