If a square+b square=13 and ab=16 Find a+b. a-b
a square+b square
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a square+b square=68 and ab=16 Find (a+b)(a-b)
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- An identity
- a²+b²=13
- ab=16
- (a+b)(a-b)
we know that
(a+b)²=a²+b²+2ab
¶utting the value
(a+b)²=a²+b²+2ab
=>(a+b)²=68+2×16
=>(a+b)²=68+32
=>(a+b)²=100
=>(a+b)=√100
=>a+b=10
Again Taking
(a-b)²=a²+b²-2ab
¶utting the value
(a-b)²=a²+b²-2ab
=>(a-b)²=68-2×16
=>(a-b)²=68-32
=>(a-b)²=36
=>(a-b)=√36
=>a-b=6
Now actual value is
(a+b)(a-b)=10×6
=>a²-b²=60
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