If a square+ b square:29 and ab:10 then find the value of a subtract b
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Answer:
a-b=3
Step-by-step explanation:
(a-b)^2=a^2+b^2-2ab
given that a^2+b^2=29. and ab=10
( a-b )^2=29 - 2×10=29-20=9
(a-b)^2=9
(a-b)^2=3^2
a-b=3. (if the power are same then the bases are equal)
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