if a square + b square + 3 square equals to 109 and a + b + c equals to23 then find the value of ab+bc+ca
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a² +b²+c²=109
a+b+c=23
ab+bc+ca=?
(a+b+c) whole square =a²+b²+c²+2ab+2bc+2ca
23 whole square=109+2(ab+bc+ca)
529=109+2(ab+bc+ca)
529-109=2(ab+bc+ca)
420=2(ab+bc+ca)
420/2=ab+bc+ca
210=ab+bc+ca
∴ANSWER=
ab+bc+ca=210
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