Question

If a square + b square = 7ab, show that, 2log(a-b)=log 5+log a+ log b, 2log (a+b) = log 9+ log a+ logb​

Answer 1

Step-by-step explanation:

a^2+b^2-2ab=5ab. a^2-b^2=5ab. (a+b)+(a-b). , so to log (a-b)^2. = log(a^2+b^2-2ab) ,so so we know a square + b square minus 2 a b equal to 5 abe so log V A B equal to log 5 + log 1 + log b and again to log a + b equal to a 2log(a+b) = log(a^2+b^2) ,=log(a^2+b^2+2ab), =log 9ab = log9+ loga+logb